The sequence of reactions is: Phenol xrightar | vedclass

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(D) Step $1$: Phenol reacts with $Zn$ dust upon heating to form Benzene $(X)$. $C_6H_5OH + Zn \xrightarrow{\Delta} C_6H_6 (X) + ZnO$. Step $2$: Benzen

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Benzoic acid

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(D) Step $1$: Phenol reacts with $Zn$ dust upon heating to form Benzene $(X)$. $C_6H_5OH + Zn \xrightarrow{\Delta} C_6H_6 (X) + ZnO$. Step $2$: Benzene undergoes Friedel-Crafts alkylation with $CH_3Cl$ in the presence of anhydrous $AlCl_3$ to form Toluene $(Y)$. $C_6H_6 + CH_3Cl \xrightarrow{	ext{Anhydrous } AlCl_3} C_6H_5CH_3 (Y) + HCl$. Step $3$: Toluene is oxidized by alkaline $KMnO_4$ upon heating to form Benzoic acid $(Z)$. $C_6H_5CH_3 \xrightarrow[\Delta]{KMnO_4} C_6H_5COOH (Z)$.

The sequence of reactions is: $Phenol$ $\xrightarrow[\Delta]{Zn \, dust} X$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3Cl} Y$ $\xrightarrow[\Delta]{KMnO_4} Z$. The final product $Z$ is:

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